Discovery of Common Mentions of org.hibernate.HibernateException in a Set

Please note that the term “collection” refers to the entire set and not individual elements within the set. This means that both sets must be identical.
One solution to this issue is that Hibernate throws an error when you try to persist multiple entity instances that share the same collection reference, which refers to the identity of the collection rather than its equality.


Solution 1:

The Hibernate error occurs when you try to persist multiple entity instances that have a common collection reference, which means they share the same collection identity instead of just having collection equality.

Please be aware that when we refer to the collection, we are not talking about the individual collection elements. This means that the value of

relatedPersons

on both

person

and

anotherPerson

must be identical. If you are experiencing issues with this, it may be due to resetting the collection after entities have been loaded or initializing both references with the same collection instance.


Solution 2:


My problem was identical to this. It occurred because BeanUtils was employed to duplicate the characteristics of one object into another, resulting in two objects that referred to the same collection.

Based on my investigation into this matter, I suggest referring to the subsequent checklist.

  • Seek out instances where <code>
    entity1.setCollection(entity2.getCollection())
    </code> and <code>
    getCollection
    </code> occur, which will yield the internal reference to the collection. It is worth noting that if getCollection() generates a fresh instance of the collection, you need not be concerned.

  • Verify the accuracy of the implementation of <code>
    clone()
    </code>.

  • Seek out <code>
    BeanUtils.copyProperties(entity1, entity2)
    </code>.


Solution 3:


An explanation is provided regarding a particular practice of attempting to save an object.

Set folders = message.getFolders();
   folders.remove(inputFolder);
   folders.add(trashFolder);
   message.setFiles(folders);
MESSAGESDAO.getMessageDAO().save(message);

It is unnecessary to assign the updated object to its parent object.

message.setFiles(folders);

To save your parent object, all you need to do is keep it simple and follow these steps.

Set folders = message.getFolders();
   folders.remove(inputFolder);
   folders.add(trashFolder);
   // Not set updated object here
MESSAGESDAO.getMessageDAO().save(message);

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