Code example to avoid KeyError in Python dictionary

The first solution involves using a try-except block to catch KeyErrors and handle them appropriately. Alternatively, the second solution recommends using the get() method to retrieve values from the dictionary, which returns None if the key is not found. Another suggestion is to use the setdefault() method to set a default value for missing keys. Python raises a KeyError whenever a non-existent key is requested from a dictionary.


Solution 1:

Your dictionary has keys:

>>> a.keys()
['b673d818a57f4cdeb549c0cbe152ed51', 'afaf178a0a3e4f91812d36a3c3289dbd', 'cd1800ef65ea4ac7a65effed5ed420d0']

To access the values, it is recommended that you utilize one of those methods instead of iterating over the keys.

for k in a.keys() :
    pass # put something here

Or you may iterate over the values:

for v in a.values() :
    pass # put something here

Or you may iterate over both:

for k,v in a.items() :
    pass # put something here


Solution 2:


In Python, a

KeyError

is raised when a key that is not in the dictionary is requested for a

dict()

object.

As an illustration, take the dictionary provided in your post.

>>> a.keys()
dict_keys(['afaf178a0a3e4f91812d36a3c3289dbd', 'cd1800ef65ea4ac7a65effed5ed420d0', 'b673d818a57f4cdeb549c0cbe152ed51'])

As the

0

is not included in the given dictionary, it leads to the occurrence of

KeyError

.

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